63x^2+13x-28=0

Solution for 63x^2+13x-28=0 equation:

63x^2+13x-28=0

a = 63; b = 13; c = -28;
Δ = b2-4ac
Δ = 132-4·63·(-28)
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7225}=85$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-85}{2*63}=\frac{-98}{126}
=-7/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+85}{2*63}=\frac{72}{126}
=4/7
$